131001333131 has 2 divisors, whose sum is σ = 131001333132. Its totient is φ = 131001333130.

The previous prime is 131001333119. The next prime is 131001333139. The reversal of 131001333131 is 131333100131.

It is a strong prime.

It is an emirp because it is prime and its reverse (131333100131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131001333131 is a prime.

It is a super-2 number, since 2×131001333131² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131001333139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500666565 + 65500666566.

It is an arithmetic number, because the mean of its divisors is an integer number (65500666566).

Almost surely, 2^131001333131 is an apocalyptic number.

131001333131 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001333131 is an equidigital number, since it uses as much as digits as its factorization.

131001333131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 131001333131 its reverse (131333100131), we get a palindrome (262334433262).

The spelling of 131001333131 in words is "one hundred thirty-one billion, one million, three hundred thirty-three thousand, one hundred thirty-one".