131001341334133 has 4 divisors (see below), whose sum is σ = 138707302589100. Its totient is φ = 123295380079168.

The previous prime is 131001341334113. The next prime is 131001341334137. The reversal of 131001341334133 is 331433143100131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 101049177591684 + 29952163742449 = 10052322^2 + 5472857^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131001341334133 is a prime.

It is a super-2 number, since 2×131001341334133² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131001341334095 and 131001341334104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131001341334137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3852980627458 + ... + 3852980627491.

It is an arithmetic number, because the mean of its divisors is an integer number (34676825647275).

Almost surely, 2^{131001341334133} is an apocalyptic number.

It is an amenable number.

131001341334133 is a deficient number, since it is larger than the sum of its proper divisors (7705961254967).

131001341334133 is an equidigital number, since it uses as much as digits as its factorization.

131001341334133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7705961254966.

The product of its (nonzero) digits is 11664, while the sum is 31.

Adding to 131001341334133 its reverse (331433143100131), we get a palindrome (462434484434264).

The spelling of 131001341334133 in words is "one hundred thirty-one trillion, one billion, three hundred forty-one million, three hundred thirty-four thousand, one hundred thirty-three".