131001341401163 has 2 divisors, whose sum is σ = 131001341401164. Its totient is φ = 131001341401162.

The previous prime is 131001341401153. The next prime is 131001341401207. The reversal of 131001341401163 is 361104143100131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131001341401163 is a prime.

It is a super-2 number, since 2×131001341401163² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131001341401153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500670700581 + 65500670700582.

It is an arithmetic number, because the mean of its divisors is an integer number (65500670700582).

Almost surely, 2^{131001341401163} is an apocalyptic number.

131001341401163 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001341401163 is an equidigital number, since it uses as much as digits as its factorization.

131001341401163 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 29.

Adding to 131001341401163 its reverse (361104143100131), we get a palindrome (492105484501294).

The spelling of 131001341401163 in words is "one hundred thirty-one trillion, one billion, three hundred forty-one million, four hundred one thousand, one hundred sixty-three".