Base | Representation |
---|---|
bin | 11000011001101010… |
… | …00100010010000110 |
3 | 1020210222020001020120 |
4 | 30030311010102012 |
5 | 203312113432104 |
6 | 10003525242410 |
7 | 642430230660 |
oct | 141465042206 |
9 | 36728201216 |
10 | 13100139654 |
11 | 56127618a8 |
12 | 2657263406 |
13 | 130a063c34 |
14 | 8c3b95530 |
15 | 51a132cd9 |
hex | 30cd44486 |
13100139654 has 16 divisors (see below), whose sum is σ = 29943176448. Its totient is φ = 3742897032.
The previous prime is 13100139643. The next prime is 13100139659. The reversal of 13100139654 is 45693100131.
It is a super-2 number, since 2×131001396542 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13100139659) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 155954002 + ... + 155954085.
It is an arithmetic number, because the mean of its divisors is an integer number (1871448528).
Almost surely, 213100139654 is an apocalyptic number.
13100139654 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13100139654 is an abundant number, since it is smaller than the sum of its proper divisors (16843036794).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100139654 is a wasteful number, since it uses less digits than its factorization.
13100139654 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 311908099.
The product of its (nonzero) digits is 9720, while the sum is 33.
Adding to 13100139654 its reverse (45693100131), we get a palindrome (58793239785).
The spelling of 13100139654 in words is "thirteen billion, one hundred million, one hundred thirty-nine thousand, six hundred fifty-four".
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