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1310014003 = 9713505299
BaseRepresentation
bin100111000010101…
…0011101000110011
310101022000121101011
41032011103220303
510140330422003
6333554051351
744314635544
oct11605235063
93338017334
101310014003
11612517a01
12306879b57
1317b53301c
14c5daa4cb
157a01c46d
hex4e153a33

1310014003 has 4 divisors (see below), whose sum is σ = 1323519400. Its totient is φ = 1296508608.

The previous prime is 1310013973. The next prime is 1310014007. The reversal of 1310014003 is 3004100131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310014003 - 213 = 1310005811 is a prime.

It is a super-2 number, since 2×13100140032 = 3432273376112168018, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310014007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6752553 + ... + 6752746.

It is an arithmetic number, because the mean of its divisors is an integer number (330879850).

Almost surely, 21310014003 is an apocalyptic number.

1310014003 is a deficient number, since it is larger than the sum of its proper divisors (13505397).

1310014003 is an equidigital number, since it uses as much as digits as its factorization.

1310014003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13505396.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1310014003 is about 36194.1155852716. The cubic root of 1310014003 is about 1094.1880800420.

Adding to 1310014003 its reverse (3004100131), we get a palindrome (4314114134).

The spelling of 1310014003 in words is "one billion, three hundred ten million, fourteen thousand, three".

Divisors: 1 97 13505299 1310014003