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1310014007 is a prime number
BaseRepresentation
bin100111000010101…
…0011101000110111
310101022000121101022
41032011103220313
510140330422012
6333554051355
744314635551
oct11605235067
93338017338
101310014007
11612517a05
12306879b5b
1317b533023
14c5daa4d1
157a01c472
hex4e153a37

1310014007 has 2 divisors, whose sum is σ = 1310014008. Its totient is φ = 1310014006.

The previous prime is 1310013973. The next prime is 1310014009. The reversal of 1310014007 is 7004100131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310014007 - 226 = 1242905143 is a prime.

It is a super-2 number, since 2×13100140072 = 3432273397072392098, which contains 22 as substring.

Together with 1310014009, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310014009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655007003 + 655007004.

It is an arithmetic number, because the mean of its divisors is an integer number (655007004).

Almost surely, 21310014007 is an apocalyptic number.

1310014007 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310014007 is an equidigital number, since it uses as much as digits as its factorization.

1310014007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 1310014007 is about 36194.1156405292. The cubic root of 1310014007 is about 1094.1880811557.

Adding to 1310014007 its reverse (7004100131), we get a palindrome (8314114138).

The spelling of 1310014007 in words is "one billion, three hundred ten million, fourteen thousand, seven".