13100140061323 has 8 divisors (see below), whose sum is σ = 15031236407040. Its totient is φ = 11183955657000.

The previous prime is 13100140061279. The next prime is 13100140061347. The reversal of 13100140061323 is 32316004100131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13100140061323 - 2¹³ = 13100140053131 is a prime.

It is a super-3 number, since 3×13100140061323³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (13100140061123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3727983463 + ... + 3727986976.

It is an arithmetic number, because the mean of its divisors is an integer number (1878904550880).

Almost surely, 2^{13100140061323} is an apocalyptic number.

13100140061323 is a deficient number, since it is larger than the sum of its proper divisors (1931096345717).

13100140061323 is an equidigital number, since it uses as much as digits as its factorization.

13100140061323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7455970697.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13100140061323 its reverse (32316004100131), we get a palindrome (45416144161454).

The spelling of 13100140061323 in words is "thirteen trillion, one hundred billion, one hundred forty million, sixty-one thousand, three hundred twenty-three".