13100140061347 has 2 divisors, whose sum is σ = 13100140061348. Its totient is φ = 13100140061346.

The previous prime is 13100140061279. The next prime is 13100140061369. The reversal of 13100140061347 is 74316004100131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13100140061347 - 2³¹ = 13097992577699 is a prime.

It is a super-2 number, since 2×13100140061347² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13100140061377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550070030673 + 6550070030674.

It is an arithmetic number, because the mean of its divisors is an integer number (6550070030674).

Almost surely, 2^{13100140061347} is an apocalyptic number.

13100140061347 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100140061347 is an equidigital number, since it uses as much as digits as its factorization.

13100140061347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 13100140061347 its reverse (74316004100131), we get a palindrome (87416144161478).

The spelling of 13100140061347 in words is "thirteen trillion, one hundred billion, one hundred forty million, sixty-one thousand, three hundred forty-seven".