131001402010322 has 4 divisors (see below), whose sum is σ = 196502103015486. Its totient is φ = 65500701005160.

The previous prime is 131001402010247. The next prime is 131001402010327. The reversal of 131001402010322 is 223010204100131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 123381643537441 + 7619758472881 = 11107729^2 + 2760391^2 .

It is a super-2 number, since 2×131001402010322² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131001402010294 and 131001402010303.

It is not an unprimeable number, because it can be changed into a prime (131001402010327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32750350502579 + ... + 32750350502582.

Almost surely, 2^{131001402010322} is an apocalyptic number.

131001402010322 is a deficient number, since it is larger than the sum of its proper divisors (65500701005164).

131001402010322 is an equidigital number, since it uses as much as digits as its factorization.

131001402010322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65500701005163.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 131001402010322 its reverse (223010204100131), we get a palindrome (354011606110453).

The spelling of 131001402010322 in words is "one hundred thirty-one trillion, one billion, four hundred two million, ten thousand, three hundred twenty-two".