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131001402010247 is a prime number
BaseRepresentation
bin11101110010010100100100…
…000010000010101010000111
3122011211121111221120012202022
4131302110210002002222013
5114132311332403311442
61142341114022233355
736410352602305106
oct3562244402025207
9564747457505668
10131001402010247
113881742326517a
1212838b4858585b
1358134c1154492
14244c7048bc03d
1510229a8e503d2
hex772524082a87

131001402010247 has 2 divisors, whose sum is σ = 131001402010248. Its totient is φ = 131001402010246.

The previous prime is 131001402010201. The next prime is 131001402010327. The reversal of 131001402010247 is 742010204100131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131001402010247 - 218 = 131001401748103 is a prime.

It is a super-2 number, since 2×1310014020102472 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131001402018247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500701005123 + 65500701005124.

It is an arithmetic number, because the mean of its divisors is an integer number (65500701005124).

Almost surely, 2131001402010247 is an apocalyptic number.

131001402010247 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001402010247 is an equidigital number, since it uses as much as digits as its factorization.

131001402010247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 131001402010247 its reverse (742010204100131), we get a palindrome (873011606110378).

The spelling of 131001402010247 in words is "one hundred thirty-one trillion, one billion, four hundred two million, ten thousand, two hundred forty-seven".