131001412301320 has 128 divisors (see below), whose sum is σ = 334858828999680. Its totient is φ = 45692236800000.

The previous prime is 131001412301303. The next prime is 131001412301321. The reversal of 131001412301320 is 23103214100131.

It is a super-2 number, since 2×131001412301320² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 131001412301291 and 131001412301300.

It is not an unprimeable number, because it can be changed into a prime (131001412301321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40955181 + ... + 44037820.

It is an arithmetic number, because the mean of its divisors is an integer number (2616084601560).

Almost surely, 2^{131001412301320} is an apocalyptic number.

131001412301320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131001412301320 is an abundant number, since it is smaller than the sum of its proper divisors (203857416698360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131001412301320 is a wasteful number, since it uses less digits than its factorization.

131001412301320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84993167 (or 84993163 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 131001412301320 its reverse (23103214100131), we get a palindrome (154104626401451).

The spelling of 131001412301320 in words is "one hundred thirty-one trillion, one billion, four hundred twelve million, three hundred one thousand, three hundred twenty".