Base | Representation |
---|---|
bin | 10011000100000011010… |
… | …010100011100101110100 |
3 | 11122020101120011102202120 |
4 | 103010003102203211310 |
5 | 132430410134040200 |
6 | 2441452011435540 |
7 | 163434344103510 |
oct | 23040322434564 |
9 | 4566346142676 |
10 | 1310020221300 |
11 | 46563829881a |
12 | 191a83155bb0 |
13 | 966c404497b |
14 | 47596293140 |
15 | 241239799a0 |
hex | 131034a3974 |
1310020221300 has 288 divisors, whose sum is σ = 4565341132800. Its totient is φ = 283328202240.
The previous prime is 1310020221241. The next prime is 1310020221317. The reversal of 1310020221300 is 31220200131.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1310020221300.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 33456534 + ... + 33495666.
Almost surely, 21310020221300 is an apocalyptic number.
1310020221300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1310020221300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2282670566400).
1310020221300 is an abundant number, since it is smaller than the sum of its proper divisors (3255320911500).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310020221300 is a wasteful number, since it uses less digits than its factorization.
1310020221300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40015 (or 40008 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 1310020221300 its reverse (31220200131), we get a palindrome (1341240421431).
The spelling of 1310020221300 in words is "one trillion, three hundred ten billion, twenty million, two hundred twenty-one thousand, three hundred".
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