Base | Representation |
---|---|
bin | 11101110010010101001101… |
… | …110101101101010110101010 |
3 | 122011211200022211101112111112 |
4 | 131302111031311231112222 |
5 | 114132314301433422310 |
6 | 1142341311400030322 |
7 | 36410406150221342 |
oct | 3562251565552652 |
9 | 564750284345445 |
10 | 131002103420330 |
11 | 38817753187a2a |
12 | 128391034623a2 |
13 | 58135a356862c |
14 | 244c76db01d22 |
15 | 10229ea800705 |
hex | 77254dd6d5aa |
131002103420330 has 16 divisors (see below), whose sum is σ = 236380323538440. Its totient is φ = 52272721949952.
The previous prime is 131002103420329. The next prime is 131002103420369. The reversal of 131002103420330 is 33024301200131.
It can be written as a sum of positive squares in 4 ways, for example, as 129861955698601 + 1140147721729 = 11395699^2 + 1067777^2 .
It is a super-2 number, since 2×1310021034203302 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131002103420296 and 131002103420305.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16014922979 + ... + 16014931158.
Almost surely, 2131002103420330 is an apocalyptic number.
131002103420330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131002103420330 is a deficient number, since it is larger than the sum of its proper divisors (105378220118110).
131002103420330 is a wasteful number, since it uses less digits than its factorization.
131002103420330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32029854553.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 131002103420330 its reverse (33024301200131), we get a palindrome (164026404620461).
The spelling of 131002103420330 in words is "one hundred thirty-one trillion, two billion, one hundred three million, four hundred twenty thousand, three hundred thirty".
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