Base | Representation |
---|---|
bin | 111101000000001010… |
… | …1011101111011000001 |
3 | 110112010202121201200221 |
4 | 1322000111131323001 |
5 | 4121243021130423 |
6 | 140103114143041 |
7 | 12315232506331 |
oct | 1720025357301 |
9 | 415122551627 |
10 | 131002130113 |
11 | 50615318338 |
12 | 21480421a81 |
13 | c4796a942a |
14 | 64aa60d0c1 |
15 | 361ad15e5d |
hex | 1e8055dec1 |
131002130113 has 2 divisors, whose sum is σ = 131002130114. Its totient is φ = 131002130112.
The previous prime is 131002130047. The next prime is 131002130117. The reversal of 131002130113 is 311031200131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 114468542224 + 16533587889 = 338332^2 + 128583^2 .
It is a cyclic number.
It is not a de Polignac number, because 131002130113 - 225 = 130968575681 is a prime.
It is not a weakly prime, because it can be changed into another prime (131002130117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501065056 + 65501065057.
It is an arithmetic number, because the mean of its divisors is an integer number (65501065057).
Almost surely, 2131002130113 is an apocalyptic number.
It is an amenable number.
131002130113 is a deficient number, since it is larger than the sum of its proper divisors (1).
131002130113 is an equidigital number, since it uses as much as digits as its factorization.
131002130113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131002130113 its reverse (311031200131), we get a palindrome (442033330244).
The spelling of 131002130113 in words is "one hundred thirty-one billion, two million, one hundred thirty thousand, one hundred thirteen".
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