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131002301219 is a prime number
BaseRepresentation
bin111101000000001011…
…0000111101100100011
3110112010202221102102012
41322000112013230203
54121243042114334
6140103121543135
712315234121226
oct1720026075443
9415122842365
10131002301219
1150615424949
12214804a4aab
13c47973928a
1464aa6555bd
15361ad4b9ce
hex1e80587b23

131002301219 has 2 divisors, whose sum is σ = 131002301220. Its totient is φ = 131002301218.

The previous prime is 131002301201. The next prime is 131002301231. The reversal of 131002301219 is 912103200131.

It is a strong prime.

It is an emirp because it is prime and its reverse (912103200131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131002301219 - 28 = 131002300963 is a prime.

It is a super-2 number, since 2×1310023012192 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131002301194 and 131002301203.

It is not a weakly prime, because it can be changed into another prime (131002301299) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65501150609 + 65501150610.

It is an arithmetic number, because the mean of its divisors is an integer number (65501150610).

Almost surely, 2131002301219 is an apocalyptic number.

131002301219 is a deficient number, since it is larger than the sum of its proper divisors (1).

131002301219 is an equidigital number, since it uses as much as digits as its factorization.

131002301219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 23.

The spelling of 131002301219 in words is "one hundred thirty-one billion, two million, three hundred one thousand, two hundred nineteen".