Base | Representation |
---|---|
bin | 11000011001101011… |
… | …01011101110110001 |
3 | 1020210222112020212222 |
4 | 30030311223232301 |
5 | 203312134114413 |
6 | 10003532530425 |
7 | 642431503025 |
oct | 141465535661 |
9 | 36728466788 |
10 | 13100301233 |
11 | 5612862238 |
12 | 2657320a15 |
13 | 130a0bc646 |
14 | 8c3bd8385 |
15 | 51a165b08 |
hex | 30cd6bbb1 |
13100301233 has 2 divisors, whose sum is σ = 13100301234. Its totient is φ = 13100301232.
The previous prime is 13100301217. The next prime is 13100301239. The reversal of 13100301233 is 33210300131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8477253184 + 4623048049 = 92072^2 + 67993^2 .
It is a cyclic number.
It is not a de Polignac number, because 13100301233 - 24 = 13100301217 is a prime.
It is not a weakly prime, because it can be changed into another prime (13100301239) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550150616 + 6550150617.
It is an arithmetic number, because the mean of its divisors is an integer number (6550150617).
Almost surely, 213100301233 is an apocalyptic number.
It is an amenable number.
13100301233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100301233 is an equidigital number, since it uses as much as digits as its factorization.
13100301233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 13100301233 its reverse (33210300131), we get a palindrome (46310601364).
The spelling of 13100301233 in words is "thirteen billion, one hundred million, three hundred one thousand, two hundred thirty-three".
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