Base | Representation |
---|---|
bin | 1011111010100010011011… |
… | …0011100011001010000001 |
3 | 1201101101011112002111220112 |
4 | 2332220212303203022001 |
5 | 3204113404113102403 |
6 | 43510110105321105 |
7 | 2521315451523521 |
oct | 276504663431201 |
9 | 51341145074815 |
10 | 13100301300353 |
11 | 41a0896618253 |
12 | 1576b14496195 |
13 | 740478a2c797 |
14 | 3340b50b7681 |
15 | 17ab8008a9d8 |
hex | bea26ce3281 |
13100301300353 has 2 divisors, whose sum is σ = 13100301300354. Its totient is φ = 13100301300352.
The previous prime is 13100301300287. The next prime is 13100301300377. The reversal of 13100301300353 is 35300310300131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12828309845569 + 271991454784 = 3581663^2 + 521528^2 .
It is a cyclic number.
It is not a de Polignac number, because 13100301300353 - 210 = 13100301299329 is a prime.
It is not a weakly prime, because it can be changed into another prime (13100301300953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550150650176 + 6550150650177.
It is an arithmetic number, because the mean of its divisors is an integer number (6550150650177).
Almost surely, 213100301300353 is an apocalyptic number.
It is an amenable number.
13100301300353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100301300353 is an equidigital number, since it uses as much as digits as its factorization.
13100301300353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1215, while the sum is 23.
Adding to 13100301300353 its reverse (35300310300131), we get a palindrome (48400611600484).
The spelling of 13100301300353 in words is "thirteen trillion, one hundred billion, three hundred one million, three hundred thousand, three hundred fifty-three".
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