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13100332300023 = 34366777433341
BaseRepresentation
bin1011111010100010100010…
…1001110011011011110111
31201101101020200102110110110
42332220220221303123313
53204113440032100043
643510113133554103
72521316306154543
oct276505051633367
951341220373413
1013100332300023
1141a0902070811
121576b22945933
13740482294797
143340b9266a23
1517ab82b60b33
hexbea28a736f7

13100332300023 has 4 divisors (see below), whose sum is σ = 17467109733368. Its totient is φ = 8733554866680.

The previous prime is 13100332299917. The next prime is 13100332300039. The reversal of 13100332300023 is 32000323300131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13100332300023 - 29 = 13100332299511 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13100332300063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183388716668 + ... + 2183388716673.

It is an arithmetic number, because the mean of its divisors is an integer number (4366777433342).

Almost surely, 213100332300023 is an apocalyptic number.

13100332300023 is a deficient number, since it is larger than the sum of its proper divisors (4366777433345).

13100332300023 is an equidigital number, since it uses as much as digits as its factorization.

13100332300023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4366777433344.

The product of its (nonzero) digits is 972, while the sum is 21.

Adding to 13100332300023 its reverse (32000323300131), we get a palindrome (45100655600154).

The spelling of 13100332300023 in words is "thirteen trillion, one hundred billion, three hundred thirty-two million, three hundred thousand, twenty-three".

Divisors: 1 3 4366777433341 13100332300023