131004044133 has 4 divisors (see below), whose sum is σ = 174672058848. Its totient is φ = 87336029420.

The previous prime is 131004044071. The next prime is 131004044137. The reversal of 131004044133 is 331440400131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131004044133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131004044137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21834007353 + ... + 21834007358.

It is an arithmetic number, because the mean of its divisors is an integer number (43668014712).

Almost surely, 2^131004044133 is an apocalyptic number.

It is an amenable number.

131004044133 is a deficient number, since it is larger than the sum of its proper divisors (43668014715).

131004044133 is an equidigital number, since it uses as much as digits as its factorization.

131004044133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43668014714.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 131004044133 its reverse (331440400131), we get a palindrome (462444444264).

The spelling of 131004044133 in words is "one hundred thirty-one billion, four million, forty-four thousand, one hundred thirty-three".