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13100413421122 = 26550206710561
BaseRepresentation
bin1011111010100010110101…
…1111010000011001000010
31201101101110100001211200121
42332220231133100121002
53204114121313433442
643510125152410454
72521321312530316
oct276505537203102
951341410054617
1013100413421122
1141a0943938245
121576b45b46a2a
13740496028231
143340c5d41b46
1517ab89d36967
hexbea2d7d0642

13100413421122 has 4 divisors (see below), whose sum is σ = 19650620131686. Its totient is φ = 6550206710560.

The previous prime is 13100413421087. The next prime is 13100413421141. The reversal of 13100413421122 is 22112431400131.

13100413421122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12845134848121 + 255278573001 = 3584011^2 + 505251^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275103355279 + ... + 3275103355282.

Almost surely, 213100413421122 is an apocalyptic number.

13100413421122 is a deficient number, since it is larger than the sum of its proper divisors (6550206710564).

13100413421122 is an equidigital number, since it uses as much as digits as its factorization.

13100413421122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6550206710563.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13100413421122 its reverse (22112431400131), we get a palindrome (35212844821253).

The spelling of 13100413421122 in words is "thirteen trillion, one hundred billion, four hundred thirteen million, four hundred twenty-one thousand, one hundred twenty-two".

Divisors: 1 2 6550206710561 13100413421122