Base | Representation |
---|---|
bin | 1011111010100010110111… |
… | …1101000110010110010001 |
3 | 1201101101110212210022002010 |
4 | 2332220231331012112101 |
5 | 3204114130314304210 |
6 | 43510130032213133 |
7 | 2521321436162403 |
oct | 276505575062621 |
9 | 51341425708063 |
10 | 13100421244305 |
11 | 41a09482a098a |
12 | 1576b4869a1a9 |
13 | 740497837035 |
14 | 3340c6dbab73 |
15 | 17ab8a87e920 |
hex | bea2df46591 |
13100421244305 has 16 divisors (see below), whose sum is σ = 21304291598784. Its totient is φ = 6872352127680.
The previous prime is 13100421244283. The next prime is 13100421244397. The reversal of 13100421244305 is 50344212400131.
It is not a de Polignac number, because 13100421244305 - 211 = 13100421242257 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7158699219 + ... + 7158701048.
It is an arithmetic number, because the mean of its divisors is an integer number (1331518224924).
Almost surely, 213100421244305 is an apocalyptic number.
13100421244305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13100421244305 is a deficient number, since it is larger than the sum of its proper divisors (8203870354479).
13100421244305 is a wasteful number, since it uses less digits than its factorization.
13100421244305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14317400336.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 13100421244305 its reverse (50344212400131), we get a palindrome (63444633644436).
The spelling of 13100421244305 in words is "thirteen trillion, one hundred billion, four hundred twenty-one million, two hundred forty-four thousand, three hundred five".
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