Base | Representation |
---|---|
bin | 1011111010100010110111… |
… | …1101000110010110010000 |
3 | 1201101101110212210022002002 |
4 | 2332220231331012112100 |
5 | 3204114130314304204 |
6 | 43510130032213132 |
7 | 2521321436162402 |
oct | 276505575062620 |
9 | 51341425708062 |
10 | 13100421244304 |
11 | 41a09482a0989 |
12 | 1576b4869a1a8 |
13 | 740497837034 |
14 | 3340c6dbab72 |
15 | 17ab8a87e91e |
hex | bea2df46590 |
13100421244304 has 10 divisors (see below), whose sum is σ = 25382066160870. Its totient is φ = 6550210622144.
The previous prime is 13100421244283. The next prime is 13100421244397. The reversal of 13100421244304 is 40344212400131.
It can be written as a sum of positive squares in only one way, i.e., 12179681203600 + 920740040704 = 3489940^2 + 959552^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 409388163869 + ... + 409388163900.
It is an arithmetic number, because the mean of its divisors is an integer number (2538206616087).
Almost surely, 213100421244304 is an apocalyptic number.
It is an amenable number.
13100421244304 is a deficient number, since it is larger than the sum of its proper divisors (12281644916566).
13100421244304 is an equidigital number, since it uses as much as digits as its factorization.
13100421244304 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 818776327777 (or 818776327771 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 13100421244304 its reverse (40344212400131), we get a palindrome (53444633644435).
The spelling of 13100421244304 in words is "thirteen trillion, one hundred billion, four hundred twenty-one million, two hundred forty-four thousand, three hundred four".
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