13100523554433 has 32 divisors (see below), whose sum is σ = 21130764364800. Its totient is φ = 7052392529856.

The previous prime is 13100523554423. The next prime is 13100523554441. The reversal of 13100523554433 is 33445532500131.

It is not a de Polignac number, because 13100523554433 - 2¹³ = 13100523546241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13100523554391 and 13100523554400.

It is not an unprimeable number, because it can be changed into a prime (13100523554423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 91641966 + ... + 91784807.

It is an arithmetic number, because the mean of its divisors is an integer number (660336386400).

Almost surely, 2^{13100523554433} is an apocalyptic number.

It is an amenable number.

13100523554433 is a deficient number, since it is larger than the sum of its proper divisors (8030240810367).

13100523554433 is a wasteful number, since it uses less digits than its factorization.

13100523554433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183426981.

The product of its (nonzero) digits is 324000, while the sum is 39.

The spelling of 13100523554433 in words is "thirteen trillion, one hundred billion, five hundred twenty-three million, five hundred fifty-four thousand, four hundred thirty-three".