131010110001301 has 4 divisors (see below), whose sum is σ = 136706201740512. Its totient is φ = 125314018262092.

The previous prime is 131010110001289. The next prime is 131010110001307. The reversal of 131010110001301 is 103100011010131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131010110001301 - 2¹¹ = 131010109999253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131010110001307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2848045869571 + ... + 2848045869616.

It is an arithmetic number, because the mean of its divisors is an integer number (34176550435128).

Almost surely, 2^{131010110001301} is an apocalyptic number.

It is an amenable number.

131010110001301 is a deficient number, since it is larger than the sum of its proper divisors (5696091739211).

131010110001301 is an equidigital number, since it uses as much as digits as its factorization.

131010110001301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5696091739210.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 131010110001301 its reverse (103100011010131), we get a palindrome (234110121011432).

The spelling of 131010110001301 in words is "one hundred thirty-one trillion, ten billion, one hundred ten million, one thousand, three hundred one".