Base | Representation |
---|---|
bin | 11101110010011100101011… |
… | …000100011001000010011011 |
3 | 122011212102222211011222210201 |
4 | 131302130223010121002123 |
5 | 114132432201130020212 |
6 | 1142345114052523031 |
7 | 36411111441101125 |
oct | 3562345304310233 |
9 | 564772884158721 |
10 | 131010110001307 |
11 | 3882009173a7a9 |
12 | 1283a778920477 |
13 | 581427b274004 |
14 | 244cccd200215 |
15 | 1022d1869ab57 |
hex | 77272b11909b |
131010110001307 has 2 divisors, whose sum is σ = 131010110001308. Its totient is φ = 131010110001306.
The previous prime is 131010110001289. The next prime is 131010110001311. The reversal of 131010110001307 is 703100011010131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131010110001307 - 243 = 122214016979099 is a prime.
It is not a weakly prime, because it can be changed into another prime (131010110401307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505055000653 + 65505055000654.
It is an arithmetic number, because the mean of its divisors is an integer number (65505055000654).
Almost surely, 2131010110001307 is an apocalyptic number.
131010110001307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131010110001307 is an equidigital number, since it uses as much as digits as its factorization.
131010110001307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63, while the sum is 19.
Adding to 131010110001307 its reverse (703100011010131), we get a palindrome (834110121011438).
The spelling of 131010110001307 in words is "one hundred thirty-one trillion, ten billion, one hundred ten million, one thousand, three hundred seven".
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