Base | Representation |
---|---|
bin | 11101110010011100101011… |
… | …001000101101010101011100 |
3 | 122011212102222220022111020000 |
4 | 131302130223020231111130 |
5 | 114132432201422224040 |
6 | 1142345114133054300 |
7 | 36411111453523440 |
oct | 3562345310552534 |
9 | 564772886274200 |
10 | 131010111133020 |
11 | 38820092342aa9 |
12 | 1283a779187390 |
13 | 581427b57c172 |
14 | 244cccd416820 |
15 | 1022d18821130 |
hex | 77272b22d55c |
131010111133020 has 480 divisors, whose sum is σ = 484338190887936. Its totient is φ = 29021307264000.
The previous prime is 131010111132937. The next prime is 131010111133043. The reversal of 131010111133020 is 20331111010131.
131010111133020 is a `hidden beast` number, since 1 + 310 + 1 + 0 + 1 + 1 + 1 + 1 + 330 + 20 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 131010111132984 and 131010111133002.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 69272899 + ... + 71138981.
Almost surely, 2131010111133020 is an apocalyptic number.
131010111133020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131010111133020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (242169095443968).
131010111133020 is an abundant number, since it is smaller than the sum of its proper divisors (353328079754916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131010111133020 is a wasteful number, since it uses less digits than its factorization.
131010111133020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1866303 (or 1866292 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 131010111133020 its reverse (20331111010131), we get a palindrome (151341222143151).
The spelling of 131010111133020 in words is "one hundred thirty-one trillion, ten billion, one hundred eleven million, one hundred thirty-three thousand, twenty".
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