Base | Representation |
---|---|
bin | 1011111010100101000101… |
… | …0011001011000000101010 |
3 | 1201101110000012121020211012 |
4 | 2332221101103023000222 |
5 | 3204121334120430010 |
6 | 43510304534103522 |
7 | 2521342226410655 |
oct | 276512123130052 |
9 | 51343005536735 |
10 | 13101014233130 |
11 | 41a1121aa019a |
12 | 15770931aaba2 |
13 | 7405606495b5 |
14 | 334141a5a89c |
15 | 17abc2965005 |
hex | bea514cb02a |
13101014233130 has 8 divisors (see below), whose sum is σ = 23581825619652. Its totient is φ = 5240405693248.
The previous prime is 13101014233093. The next prime is 13101014233163. The reversal of 13101014233130 is 3133241010131.
It can be written as a sum of positive squares in 2 ways, for example, as 13098615878401 + 2398354729 = 3619201^2 + 48973^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13101014233096 and 13101014233105.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655050711647 + ... + 655050711666.
Almost surely, 213101014233130 is an apocalyptic number.
13101014233130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13101014233130 is a deficient number, since it is larger than the sum of its proper divisors (10480811386522).
13101014233130 is a wasteful number, since it uses less digits than its factorization.
13101014233130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1310101423320.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13101014233130 its reverse (3133241010131), we get a palindrome (16234255243261).
The spelling of 13101014233130 in words is "thirteen trillion, one hundred one billion, fourteen million, two hundred thirty-three thousand, one hundred thirty".
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