Base | Representation |
---|---|
bin | 10011000100001000001… |
… | …110010101010001000100 |
3 | 11122020121022221000222020 |
4 | 103010020032111101010 |
5 | 132431042332001012 |
6 | 2441504130003140 |
7 | 163436400522303 |
oct | 23041016252104 |
9 | 4566538830866 |
10 | 1310103000132 |
11 | 46567aa97783 |
12 | 191aa6a164b0 |
13 | 96708238b24 |
14 | 475a328043a |
15 | 2412ad7ba8c |
hex | 13108395444 |
1310103000132 has 12 divisors (see below), whose sum is σ = 3056907000336. Its totient is φ = 436701000040.
The previous prime is 1310103000127. The next prime is 1310103000179. The reversal of 1310103000132 is 2310003010131.
It is a tau number, because it is divible by the number of its divisors (12).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54587624994 + ... + 54587625017.
It is an arithmetic number, because the mean of its divisors is an integer number (254742250028).
Almost surely, 21310103000132 is an apocalyptic number.
1310103000132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1310103000132 is an abundant number, since it is smaller than the sum of its proper divisors (1746804000204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310103000132 is a wasteful number, since it uses less digits than its factorization.
1310103000132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109175250018 (or 109175250016 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 1310103000132 its reverse (2310003010131), we get a palindrome (3620106010263).
Subtracting 1310103000132 from its reverse (2310003010131), we obtain a palindrome (999900009999).
The spelling of 1310103000132 in words is "one trillion, three hundred ten billion, one hundred three million, one hundred thirty-two", and thus it is an aban number.
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