Base | Representation |
---|---|
bin | 1011111010100101001001… |
… | …0011100001011101111010 |
3 | 1201101110001101100022000101 |
4 | 2332221102103201131322 |
5 | 3204121402430233310 |
6 | 43510310335430014 |
7 | 2521342522660213 |
oct | 276512223413572 |
9 | 51343041308011 |
10 | 13101031102330 |
11 | 41a1130572286 |
12 | 157709898530a |
13 | 740563ca4982 |
14 | 334143dac40a |
15 | 17abc419843a |
hex | bea524e177a |
13101031102330 has 8 divisors (see below), whose sum is σ = 23581855984212. Its totient is φ = 5240412440928.
The previous prime is 13101031102309. The next prime is 13101031102339. The reversal of 13101031102330 is 3320113010131.
It can be written as a sum of positive squares in 2 ways, for example, as 13033912283001 + 67118819329 = 3610251^2 + 259073^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13101031102298 and 13101031102307.
It is not an unprimeable number, because it can be changed into a prime (13101031102339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655051555107 + ... + 655051555126.
Almost surely, 213101031102330 is an apocalyptic number.
13101031102330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13101031102330 is a deficient number, since it is larger than the sum of its proper divisors (10480824881882).
13101031102330 is a wasteful number, since it uses less digits than its factorization.
13101031102330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1310103110240.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13101031102330 its reverse (3320113010131), we get a palindrome (16421144112461).
The spelling of 13101031102330 in words is "thirteen trillion, one hundred one billion, thirty-one million, one hundred two thousand, three hundred thirty".
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