Base | Representation |
---|---|
bin | 11101110010011100111000… |
… | …011100001011100100011001 |
3 | 122011212110120110022122120002 |
4 | 131302130320130023210121 |
5 | 114132433131042411101 |
6 | 1142345152225142345 |
7 | 36411120134001644 |
oct | 3562347034134431 |
9 | 564773513278502 |
10 | 131010334341401 |
11 | 38820197337839 |
12 | 1283a81ba8a9b5 |
13 | 58142b58a1028 |
14 | 244cd10d1aa5b |
15 | 1022d2d211d6b |
hex | 77273870b919 |
131010334341401 has 2 divisors, whose sum is σ = 131010334341402. Its totient is φ = 131010334341400.
The previous prime is 131010334341329. The next prime is 131010334341421. The reversal of 131010334341401 is 104143433010131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 72166707019801 + 58843627321600 = 8495099^2 + 7670960^2 .
It is a cyclic number.
It is not a de Polignac number, because 131010334341401 - 222 = 131010330147097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (131010334341421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505167170700 + 65505167170701.
It is an arithmetic number, because the mean of its divisors is an integer number (65505167170701).
Almost surely, 2131010334341401 is an apocalyptic number.
It is an amenable number.
131010334341401 is a deficient number, since it is larger than the sum of its proper divisors (1).
131010334341401 is an equidigital number, since it uses as much as digits as its factorization.
131010334341401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 131010334341401 its reverse (104143433010131), we get a palindrome (235153767351532).
The spelling of 131010334341401 in words is "one hundred thirty-one trillion, ten billion, three hundred thirty-four million, three hundred forty-one thousand, four hundred one".
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