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131010412224434 = 265505206112217
BaseRepresentation
bin11101110010011100111101…
…000101010001111110110010
3122011212110202212212111222212
4131302130331011101332302
5114132433311012140214
61142345204050332122
736411122101000121
oct3562347505217662
9564773685774885
10131010412224434
11388202272a2486
121283a841b8a042
1358142c8a6c972
14244cd1b3d1ab8
151022d34e9853e
hex77273d151fb2

131010412224434 has 4 divisors (see below), whose sum is σ = 196515618336654. Its totient is φ = 65505206112216.

The previous prime is 131010412224379. The next prime is 131010412224473. The reversal of 131010412224434 is 434422214010131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 130663120055209 + 347292169225 = 11430797^2 + 589315^2 .

It is a super-2 number, since 2×1310104122244342 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131010412224434.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32752603056107 + ... + 32752603056110.

Almost surely, 2131010412224434 is an apocalyptic number.

131010412224434 is a deficient number, since it is larger than the sum of its proper divisors (65505206112220).

131010412224434 is an equidigital number, since it uses as much as digits as its factorization.

131010412224434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65505206112219.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 131010412224434 its reverse (434422214010131), we get a palindrome (565432626234565).

The spelling of 131010412224434 in words is "one hundred thirty-one trillion, ten billion, four hundred twelve million, two hundred twenty-four thousand, four hundred thirty-four".

Divisors: 1 2 65505206112217 131010412224434