Base | Representation |
---|---|
bin | 1011111010100101001100… |
… | …1010101001100010110100 |
3 | 1201101110002101112111001200 |
4 | 2332221103022221202310 |
5 | 3204121420130201312 |
6 | 43510312013252500 |
7 | 2521343056545342 |
oct | 276512312514264 |
9 | 51343071474050 |
10 | 13101045553332 |
11 | 41a1138742560 |
12 | 15770a1794130 |
13 | 740566c94469 |
14 | 334145c90992 |
15 | 17abc55a00dc |
hex | bea532a98b4 |
13101045553332 has 216 divisors, whose sum is σ = 36816618908160. Its totient is φ = 3895633271040.
The previous prime is 13101045553247. The next prime is 13101045553363. The reversal of 13101045553332 is 23335554010131.
13101045553332 is a `hidden beast` number, since 1 + 3 + 10 + 104 + 5 + 5 + 533 + 3 + 2 = 666.
13101045553332 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 784344493 + ... + 784361195.
It is an arithmetic number, because the mean of its divisors is an integer number (170447309760).
Almost surely, 213101045553332 is an apocalyptic number.
13101045553332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13101045553332, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18408309454080).
13101045553332 is an abundant number, since it is smaller than the sum of its proper divisors (23715573354828).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101045553332 is a wasteful number, since it uses less digits than its factorization.
13101045553332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17411 (or 17347 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 36.
Adding to 13101045553332 its reverse (23335554010131), we get a palindrome (36436599563463).
The spelling of 13101045553332 in words is "thirteen trillion, one hundred one billion, forty-five million, five hundred fifty-three thousand, three hundred thirty-two".
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