Base | Representation |
---|---|
bin | 1011111010100101011100… |
… | …0100110001100110010001 |
3 | 1201101110020221220201210202 |
4 | 2332221113010301212101 |
5 | 3204122033421403241 |
6 | 43510322314504545 |
7 | 2521344514065515 |
oct | 276512704614621 |
9 | 51343227821722 |
10 | 13101111122321 |
11 | 41a1171757502 |
12 | 15770bb735155 |
13 | 740577741191 |
14 | 33415087c145 |
15 | 17abcb202d9b |
hex | bea57131991 |
13101111122321 has 2 divisors, whose sum is σ = 13101111122322. Its totient is φ = 13101111122320.
The previous prime is 13101111122269. The next prime is 13101111122369. The reversal of 13101111122321 is 12322111110131.
13101111122321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13073546821696 + 27564300625 = 3615736^2 + 166025^2 .
It is a cyclic number.
It is not a de Polignac number, because 13101111122321 - 218 = 13101110860177 is a prime.
It is a super-2 number, since 2×131011111223212 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13101111122293 and 13101111122302.
It is not a weakly prime, because it can be changed into another prime (13101111122621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550555561160 + 6550555561161.
It is an arithmetic number, because the mean of its divisors is an integer number (6550555561161).
Almost surely, 213101111122321 is an apocalyptic number.
It is an amenable number.
13101111122321 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101111122321 is an equidigital number, since it uses as much as digits as its factorization.
13101111122321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 13101111122321 its reverse (12322111110131), we get a palindrome (25423222232452).
The spelling of 13101111122321 in words is "thirteen trillion, one hundred one billion, one hundred eleven million, one hundred twenty-two thousand, three hundred twenty-one".
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