13101111413413 has 4 divisors (see below), whose sum is σ = 13101872813280. Its totient is φ = 13100350013548.

The previous prime is 13101111413393. The next prime is 13101111413419. The reversal of 13101111413413 is 31431411110131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101111413413 - 2⁹ = 13101111412901 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101111413419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380674123 + ... + 380708536.

It is an arithmetic number, because the mean of its divisors is an integer number (3275468203320).

Almost surely, 2^{13101111413413} is an apocalyptic number.

It is an amenable number.

13101111413413 is a deficient number, since it is larger than the sum of its proper divisors (761399867).

13101111413413 is an equidigital number, since it uses as much as digits as its factorization.

13101111413413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 761399866.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 13101111413413 its reverse (31431411110131), we get a palindrome (44532522523544).

The spelling of 13101111413413 in words is "thirteen trillion, one hundred one billion, one hundred eleven million, four hundred thirteen thousand, four hundred thirteen".