Base | Representation |
---|---|
bin | 111101000000011011… |
… | …1110001010110101001 |
3 | 110112011101112121002001 |
4 | 1322000313301112221 |
5 | 4121302321410401 |
6 | 140104035011001 |
7 | 12315402111442 |
oct | 1720067612651 |
9 | 415141477061 |
10 | 131011122601 |
11 | 5061a3aa547 |
12 | 21483439a61 |
13 | c47b507528 |
14 | 64ab8b02c9 |
15 | 361b9e0601 |
hex | 1e80df15a9 |
131011122601 has 2 divisors, whose sum is σ = 131011122602. Its totient is φ = 131011122600.
The previous prime is 131011122589. The next prime is 131011122611. The reversal of 131011122601 is 106221110131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67990041001 + 63021081600 = 260749^2 + 251040^2 .
It is an emirp because it is prime and its reverse (106221110131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131011122601 - 221 = 131009025449 is a prime.
It is not a weakly prime, because it can be changed into another prime (131011122611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505561300 + 65505561301.
It is an arithmetic number, because the mean of its divisors is an integer number (65505561301).
Almost surely, 2131011122601 is an apocalyptic number.
It is an amenable number.
131011122601 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011122601 is an equidigital number, since it uses as much as digits as its factorization.
131011122601 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 131011122601 its reverse (106221110131), we get a palindrome (237232232732).
The spelling of 131011122601 in words is "one hundred thirty-one billion, eleven million, one hundred twenty-two thousand, six hundred one".
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