13101113001111 has 4 divisors (see below), whose sum is σ = 17468150668152. Its totient is φ = 8734075334072.

The previous prime is 13101113001103. The next prime is 13101113001143. The reversal of 13101113001111 is 11110031110131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101113001111 - 2³ = 13101113001103 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101113001611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183518833516 + ... + 2183518833521.

It is an arithmetic number, because the mean of its divisors is an integer number (4367037667038).

Almost surely, 2^{13101113001111} is an apocalyptic number.

13101113001111 is a deficient number, since it is larger than the sum of its proper divisors (4367037667041).

13101113001111 is an equidigital number, since it uses as much as digits as its factorization.

13101113001111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4367037667040.

The product of its (nonzero) digits is 9, while the sum is 15.

Adding to 13101113001111 its reverse (11110031110131), we get a palindrome (24211144111242).

The spelling of 13101113001111 in words is "thirteen trillion, one hundred one billion, one hundred thirteen million, one thousand, one hundred eleven".