Base | Representation |
---|---|
bin | 1011111010100101011100… |
… | …1011111100010010110111 |
3 | 1201101110021002110012001202 |
4 | 2332221113023330102313 |
5 | 3204122034412014033 |
6 | 43510322423043115 |
7 | 2521344536052236 |
oct | 276512713742267 |
9 | 51343232405052 |
10 | 13101113001143 |
11 | 41a1172820052 |
12 | 15771002a049b |
13 | 740577c4b3cb |
14 | 334150c0ab1d |
15 | 17abcb4748e8 |
hex | bea572fc4b7 |
13101113001143 has 2 divisors, whose sum is σ = 13101113001144. Its totient is φ = 13101113001142.
The previous prime is 13101113001103. The next prime is 13101113001187. The reversal of 13101113001143 is 34110031110131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13101113001143 - 224 = 13101096223927 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13101113001103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550556500571 + 6550556500572.
It is an arithmetic number, because the mean of its divisors is an integer number (6550556500572).
Almost surely, 213101113001143 is an apocalyptic number.
13101113001143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101113001143 is an equidigital number, since it uses as much as digits as its factorization.
13101113001143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 13101113001143 its reverse (34110031110131), we get a palindrome (47211144111274).
The spelling of 13101113001143 in words is "thirteen trillion, one hundred one billion, one hundred thirteen million, one thousand, one hundred forty-three".
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