Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …110111011011000000101011 |
3 | 122011212112121220111220000002 |
4 | 131302131213313123000223 |
5 | 114132441243240333231 |
6 | 1142345403211133215 |
7 | 36411145635043256 |
oct | 3562354767330053 |
9 | 564775556456002 |
10 | 131011130011691 |
11 | 38820565490696 |
12 | 1283aa0244420b |
13 | 58143b1699257 |
14 | 244cd8887a09d |
15 | 1022d77ed10cb |
hex | 772767ddb02b |
131011130011691 has 2 divisors, whose sum is σ = 131011130011692. Its totient is φ = 131011130011690.
The previous prime is 131011130011639. The next prime is 131011130011709. The reversal of 131011130011691 is 196110031110131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131011130011691 is a prime.
It is not a weakly prime, because it can be changed into another prime (131011130013691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505565005845 + 65505565005846.
It is an arithmetic number, because the mean of its divisors is an integer number (65505565005846).
Almost surely, 2131011130011691 is an apocalyptic number.
131011130011691 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011130011691 is an equidigital number, since it uses as much as digits as its factorization.
131011130011691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 29.
The spelling of 131011130011691 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty million, eleven thousand, six hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •