Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …111011101100010110111010 |
3 | 122011212112121222121202211220 |
4 | 131302131213323230112322 |
5 | 114132441244032200242 |
6 | 1142345403251132510 |
7 | 36411145650415431 |
oct | 3562354773542672 |
9 | 564775558552756 |
10 | 131011131131322 |
11 | 38820566085902 |
12 | 1283aa028a4136 |
13 | 58143b199ba60 |
14 | 244cd88a8c118 |
15 | 1022d78152bec |
hex | 772767eec5ba |
131011131131322 has 16 divisors (see below), whose sum is σ = 282177820898400. Its totient is φ = 40311117271152.
The previous prime is 131011131131311. The next prime is 131011131131327. The reversal of 131011131131322 is 223131131110131.
It is a junction number, because it is equal to n+sod(n) for n = 131011131131292 and 131011131131301.
It is not an unprimeable number, because it can be changed into a prime (131011131131327) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 839814943072 + ... + 839814943227.
It is an arithmetic number, because the mean of its divisors is an integer number (17636113806150).
Almost surely, 2131011131131322 is an apocalyptic number.
131011131131322 is an abundant number, since it is smaller than the sum of its proper divisors (151166689767078).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011131131322 is a wasteful number, since it uses less digits than its factorization.
131011131131322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1679629886317.
The product of its (nonzero) digits is 324, while the sum is 24.
Adding to 131011131131322 its reverse (223131131110131), we get a palindrome (354142262241453).
The spelling of 131011131131322 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty-one million, one hundred thirty-one thousand, three hundred twenty-two".
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