131011141020043 has 2 divisors, whose sum is σ = 131011141020044. Its totient is φ = 131011141020042.

The previous prime is 131011141020013. The next prime is 131011141020059. The reversal of 131011141020043 is 340020141110131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131011141020043 - 2²¹ = 131011138922891 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131011141019996 and 131011141020023.

It is not a weakly prime, because it can be changed into another prime (131011141020013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505570510021 + 65505570510022.

It is an arithmetic number, because the mean of its divisors is an integer number (65505570510022).

Almost surely, 2^{131011141020043} is an apocalyptic number.

131011141020043 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011141020043 is an equidigital number, since it uses as much as digits as its factorization.

131011141020043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 131011141020043 its reverse (340020141110131), we get a palindrome (471031282130174).

The spelling of 131011141020043 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-one million, twenty thousand, forty-three".