131011141226857 has 2 divisors, whose sum is σ = 131011141226858. Its totient is φ = 131011141226856.

The previous prime is 131011141226839. The next prime is 131011141226929. The reversal of 131011141226857 is 758622141110131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70445453726041 + 60565687500816 = 8393179^2 + 7782396^2 .

It is an emirp because it is prime and its reverse (758622141110131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131011141226857 is a prime.

It is not a weakly prime, because it can be changed into another prime (131011141226807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505570613428 + 65505570613429.

It is an arithmetic number, because the mean of its divisors is an integer number (65505570613429).

Almost surely, 2^{131011141226857} is an apocalyptic number.

It is an amenable number.

131011141226857 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011141226857 is an equidigital number, since it uses as much as digits as its factorization.

131011141226857 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 80640, while the sum is 43.

Adding to 131011141226857 its reverse (758622141110131), we get a palindrome (889633282336988).

The spelling of 131011141226857 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-one million, two hundred twenty-six thousand, eight hundred fifty-seven".