131011202430523 has 2 divisors, whose sum is σ = 131011202430524. Its totient is φ = 131011202430522.

The previous prime is 131011202430499. The next prime is 131011202430527. The reversal of 131011202430523 is 325034202110131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131011202430523 - 2⁴¹ = 128812179174971 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131011202430491 and 131011202430500.

It is not a weakly prime, because it can be changed into another prime (131011202430527) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505601215261 + 65505601215262.

It is an arithmetic number, because the mean of its divisors is an integer number (65505601215262).

Almost surely, 2^{131011202430523} is an apocalyptic number.

131011202430523 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011202430523 is an equidigital number, since it uses as much as digits as its factorization.

131011202430523 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 131011202430523 its reverse (325034202110131), we get a palindrome (456045404540654).

The spelling of 131011202430523 in words is "one hundred thirty-one trillion, eleven billion, two hundred two million, four hundred thirty thousand, five hundred twenty-three".