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1310112213233 is a prime number
BaseRepresentation
bin10011000100001000110…
…001011110100011110001
311122020121222021002222012
4103010020301132203301
5132431102211310413
62441505055252305
7163436542033535
oct23041061364361
94566558232865
101310112213233
1146568520a70a
12191aa9b1a095
139670a113475
14475a459bbc5
152412ba9b7a8
hex13108c5e8f1

1310112213233 has 2 divisors, whose sum is σ = 1310112213234. Its totient is φ = 1310112213232.

The previous prime is 1310112213197. The next prime is 1310112213281. The reversal of 1310112213233 is 3323122110131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 738066555664 + 572045657569 = 859108^2 + 756337^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310112213233 - 28 = 1310112212977 is a prime.

It is a super-2 number, since 2×13101122132332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310112213199 and 1310112213208.

It is not a weakly prime, because it can be changed into another prime (1310112219233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655056106616 + 655056106617.

It is an arithmetic number, because the mean of its divisors is an integer number (655056106617).

Almost surely, 21310112213233 is an apocalyptic number.

It is an amenable number.

1310112213233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310112213233 is an equidigital number, since it uses as much as digits as its factorization.

1310112213233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1310112213233 its reverse (3323122110131), we get a palindrome (4633234323364).

The spelling of 1310112213233 in words is "one trillion, three hundred ten billion, one hundred twelve million, two hundred thirteen thousand, two hundred thirty-three".