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13101122520 = 23335139197443
BaseRepresentation
bin11000011001110001…
…10100001111011000
31020211001001222111000
430030320310033120
5203312341410040
610004002305000
7642441463323
oct141470641730
936731058430
1013101122520
115613273292
122657658160
13130a319405
148c3d6d7ba
1551a279130
hex30ce343d8

13101122520 has 256 divisors, whose sum is σ = 44307648000. Its totient is φ = 3443102208.

The previous prime is 13101122519. The next prime is 13101122521. The reversal of 13101122520 is 2522110131.

13101122520 is a `hidden beast` number, since 1 + 31 + 0 + 112 + 2 + 520 = 666.

It is an interprime number because it is at equal distance from previous prime (13101122519) and next prime (13101122521).

It is a super-2 number, since 2×131011225202 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13101122493 and 13101122502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101122521) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 29573419 + ... + 29573861.

It is an arithmetic number, because the mean of its divisors is an integer number (173076750).

Almost surely, 213101122520 is an apocalyptic number.

13101122520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13101122520, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22153824000).

13101122520 is an abundant number, since it is smaller than the sum of its proper divisors (31206525480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13101122520 is a wasteful number, since it uses less digits than its factorization.

13101122520 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 799 (or 789 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 13101122520 its reverse (2522110131), we get a palindrome (15623232651).

The spelling of 13101122520 in words is "thirteen billion, one hundred one million, one hundred twenty-two thousand, five hundred twenty".