Base | Representation |
---|---|
bin | 11101110010011101101110… |
… | …000000101011000101101111 |
3 | 122011212112220002111022202220 |
4 | 131302131232000223011233 |
5 | 114132442001133201033 |
6 | 1142345421332450423 |
7 | 36411151326220554 |
oct | 3562355600530557 |
9 | 564775802438686 |
10 | 131011233100143 |
11 | 388206086a1560 |
12 | 1283aa30a79a13 |
13 | 58143c9b51736 |
14 | 244cd98432a2b |
15 | 1022d82095bb3 |
hex | 77276e02b16f |
131011233100143 has 16 divisors (see below), whose sum is σ = 190769151417600. Its totient is φ = 79314348242880.
The previous prime is 131011233100109. The next prime is 131011233100183. The reversal of 131011233100143 is 341001332110131.
It is not a de Polignac number, because 131011233100143 - 224 = 131011216322927 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131011233100103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2159946478 + ... + 2160007131.
It is an arithmetic number, because the mean of its divisors is an integer number (11923071963600).
Almost surely, 2131011233100143 is an apocalyptic number.
131011233100143 is a deficient number, since it is larger than the sum of its proper divisors (59757918317457).
131011233100143 is a wasteful number, since it uses less digits than its factorization.
131011233100143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4319954542.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 131011233100143 its reverse (341001332110131), we get a palindrome (472012565210274).
The spelling of 131011233100143 in words is "one hundred thirty-one trillion, eleven billion, two hundred thirty-three million, one hundred thousand, one hundred forty-three".
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