Base | Representation |
---|---|
bin | 1011111010100101100000… |
… | …1100110111010111101011 |
3 | 1201101110022021110212000001 |
4 | 2332221120030313113223 |
5 | 3204122103241122311 |
6 | 43510324231523431 |
7 | 2521345133524663 |
oct | 276513014672753 |
9 | 51343267425001 |
10 | 13101130020331 |
11 | 41a11813948a1 |
12 | 1577105b29577 |
13 | 74057b629b32 |
14 | 33415319b1a3 |
15 | 17abccbd74c1 |
hex | bea583375eb |
13101130020331 has 2 divisors, whose sum is σ = 13101130020332. Its totient is φ = 13101130020330.
The previous prime is 13101130020289. The next prime is 13101130020347. The reversal of 13101130020331 is 13302003110131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13101130020331 - 29 = 13101130019819 is a prime.
It is a super-2 number, since 2×131011300203312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13101130020299 and 13101130020308.
It is not a weakly prime, because it can be changed into another prime (13101130020371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550565010165 + 6550565010166.
It is an arithmetic number, because the mean of its divisors is an integer number (6550565010166).
Almost surely, 213101130020331 is an apocalyptic number.
13101130020331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101130020331 is an equidigital number, since it uses as much as digits as its factorization.
13101130020331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13101130020331 its reverse (13302003110131), we get a palindrome (26403133130462).
The spelling of 13101130020331 in words is "thirteen trillion, one hundred one billion, one hundred thirty million, twenty thousand, three hundred thirty-one".
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