Base | Representation |
---|---|
bin | 1011111010100101100001… |
… | …0000111111001110111010 |
3 | 1201101110022100111202120001 |
4 | 2332221120100333032322 |
5 | 3204122104030213424 |
6 | 43510324311023214 |
7 | 2521345145645650 |
oct | 276513020771672 |
9 | 51343270452501 |
10 | 13101131101114 |
11 | 41a1181a62901 |
12 | 157710636ab0a |
13 | 74057b917a54 |
14 | 33415339cdd0 |
15 | 17abccd4c844 |
hex | bea5843f3ba |
13101131101114 has 64 divisors (see below), whose sum is σ = 23755747018752. Its totient is φ = 5299619558400.
The previous prime is 13101131101039. The next prime is 13101131101159. The reversal of 13101131101114 is 41110113110131.
It is a super-2 number, since 2×131011311011142 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13101131101091 and 13101131101100.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 63831384 + ... + 64036300.
It is an arithmetic number, because the mean of its divisors is an integer number (371183547168).
Almost surely, 213101131101114 is an apocalyptic number.
13101131101114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13101131101114 is a deficient number, since it is larger than the sum of its proper divisors (10654615917638).
13101131101114 is a wasteful number, since it uses less digits than its factorization.
13101131101114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 208591.
The product of its (nonzero) digits is 36, while the sum is 19.
Adding to 13101131101114 its reverse (41110113110131), we get a palindrome (54211244211245).
The spelling of 13101131101114 in words is "thirteen trillion, one hundred one billion, one hundred thirty-one million, one hundred one thousand, one hundred fourteen".
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