131011432340234 has 4 divisors (see below), whose sum is σ = 196517148510354. Its totient is φ = 65505716170116.

The previous prime is 131011432340227. The next prime is 131011432340249. The reversal of 131011432340234 is 432043234110131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 99587526216025 + 31423906124209 = 9979355^2 + 5605703^2 .

It is a super-2 number, since 2×131011432340234² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 131011432340234.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32752858085057 + ... + 32752858085060.

Almost surely, 2^{131011432340234} is an apocalyptic number.

131011432340234 is a deficient number, since it is larger than the sum of its proper divisors (65505716170120).

131011432340234 is an equidigital number, since it uses as much as digits as its factorization.

131011432340234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65505716170119.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 131011432340234 its reverse (432043234110131), we get a palindrome (563054666450365).

The spelling of 131011432340234 in words is "one hundred thirty-one trillion, eleven billion, four hundred thirty-two million, three hundred forty thousand, two hundred thirty-four".