131011443229243 has 2 divisors, whose sum is σ = 131011443229244. Its totient is φ = 131011443229242.

The previous prime is 131011443229201. The next prime is 131011443229273. The reversal of 131011443229243 is 342922344110131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131011443229243 - 2²⁹ = 131010906358331 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131011443229196 and 131011443229205.

It is not a weakly prime, because it can be changed into another prime (131011443229273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505721614621 + 65505721614622.

It is an arithmetic number, because the mean of its divisors is an integer number (65505721614622).

Almost surely, 2^{131011443229243} is an apocalyptic number.

131011443229243 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011443229243 is an equidigital number, since it uses as much as digits as its factorization.

131011443229243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 40.

Adding to 131011443229243 its reverse (342922344110131), we get a palindrome (473933787339374).

The spelling of 131011443229243 in words is "one hundred thirty-one trillion, eleven billion, four hundred forty-three million, two hundred twenty-nine thousand, two hundred forty-three".