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1310117131 is a prime number
BaseRepresentation
bin100111000010110…
…1100110100001011
310101022012211211201
41032011230310023
510140342222011
6334000205031
744315545321
oct11605546413
93338184751
101310117131
11612588434
12306909777
1317b56ac4b
14c5dd5d11
157a03ccc1
hex4e16cd0b

1310117131 has 2 divisors, whose sum is σ = 1310117132. Its totient is φ = 1310117130.

The previous prime is 1310117111. The next prime is 1310117161. The reversal of 1310117131 is 1317110131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1310117131 - 229 = 773246219 is a prime.

It is a super-2 number, since 2×13101171312 = 3432813793879342322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310117099 and 1310117108.

It is not a weakly prime, because it can be changed into another prime (1310117111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655058565 + 655058566.

It is an arithmetic number, because the mean of its divisors is an integer number (655058566).

Almost surely, 21310117131 is an apocalyptic number.

1310117131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310117131 is an equidigital number, since it uses as much as digits as its factorization.

1310117131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63, while the sum is 19.

The square root of 1310117131 is about 36195.5402087053. The cubic root of 1310117131 is about 1094.2167918133.

Adding to 1310117131 its reverse (1317110131), we get a palindrome (2627227262).

The spelling of 1310117131 in words is "one billion, three hundred ten million, one hundred seventeen thousand, one hundred thirty-one".